## Chemistry: A Molecular Approach (3rd Edition)

$$131molsFe(NO_{3})_{2}$$
Convert kilograms into grams, then use molar mass to convert from grams to moles. $23.6$ $kg$ $Fe(NO_{3})_{2}\times\frac{1000 g Fe(NO_{3})_{2}}{1 kg Fe(NO_{3})_{2}}\times\frac{1 mol Fe(NO_{3})_{2}}{179.8548 g Fe(NO_{3})_{2}} =$ $131$ $mols$ $Fe(NO_{3})_{2}$