Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 64b

Answer

$$131molsFe(NO_{3})_{2}$$

Work Step by Step

Convert kilograms into grams, then use molar mass to convert from grams to moles. $23.6$ $kg$ $Fe(NO_{3})_{2}\times\frac{1000 g Fe(NO_{3})_{2}}{1 kg Fe(NO_{3})_{2}}\times\frac{1 mol Fe(NO_{3})_{2}}{179.8548 g Fe(NO_{3})_{2}} =$ $131$ $mols$ $Fe(NO_{3})_{2}$
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