Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 64a

Answer

$$0.4630 molsCF_{2}Cl_{2}$$

Work Step by Step

Use molar mass to convert from grams to moles. $55.98g CF_{2}Cl_{2}\times\frac{1 mol CF_{2}Cl_{2}}{120.9135 g CF_{2}Cl_{2}} = 0.4630 mols CF_{2}Cl_{2}$
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