Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 61d

Answer

$$0.279 mols$$

Work Step by Step

Divide masses provided by the molecular mass of the molecule/element to find the mols. Molar mass of $N_2O = 2\times(14.01, mass of nitrogen) + (16, mass of oxygen) = 44.02 gN_2O$ $\frac{12.3g N_2O in sample}{44.02gN_2O per mole} \approx 968mol N_2O$
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