Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 61a

Answer

$$0.471 Mol$$

Work Step by Step

Divide masses provided by the molecular mass of the molecule/element to find the mols. $72.5gCCl_4 \times\frac{1molCCl_4}{153.81g CCl_4}= 0.471mol$
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