# Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 44d

Calcium Fluoride - CaF$_{2}$

#### Work Step by Step

1. To begin, write the formula of the first element with its charge. Ca$^{2+}$ 2. Then write the formula of the second element (fluoride is fluorine) along with its charge. F$^{-}$ 3. Cross down the charges of both of the elements (+2 and -1) to get: $$CaF_{2}$$

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