## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic: 35a

#### Answer

Final compound formed has the formula $Ca(OH)_{2}$.

#### Work Step by Step

The metal cation is $Ca^{2+}$ The polyatomic anion is $OH^{-}$ Combine 1 $Ca^{2+}$ and 2 $OH^{-}$ to balance the charge. Final compound formed has the formula $Ca(OH)_{2}$.

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