Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 93

Answer

$3.24\times 10^{-22}\ g\ Pt $

Work Step by Step

1. Use Avogadro's number and the molar mass of platinum as conversion factors in order to determine the mass of the platinum atom. 2. $1\ atoms\ Pt\times\frac{1\ mol\ Pt}{6.022\times 10^{23}\ atoms\ Pt}\times\frac{195\ g \ Pt}{1\ mol\ Pt}= 3.24\times 10^{-22}\ g\ Pt $
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