Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 90d

Answer

$ 6.32\times 10^{3}\ kg\ Li $

Work Step by Step

1. Use Avogadro's number to convert from atoms to moles of lithium. Then use the molar mass of lithium to convert from moles to grams of lithium. Finally, convert grams into kilograms. 2. $5.48\times10^{29}\ atoms\ Li\times\frac{1\ mol\ Li}{6.022\times 10^{23}\ atoms\ Li}\times\frac{6.94\ g \ Li}{1\ mol\ Li}\times\frac{1\ kg\ Li}{1000\ g\ Li}= 6.32\times 10^{3}\ kg\ Li $
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