Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 90b

Answer

$ 794\ kg\ Ni $

Work Step by Step

1. Use Avogadro's number to convert from atoms to moles of nickel. Then use the molar mass of nickel to convert from moles to grams of nickel. Finally, convert grams into kilograms. 2. $8.15\times10^{27}\ atoms\ Ni\times\frac{1\ mol\ Ni}{6.022\times 10^{23}\ atoms\ Ni}\times\frac{58.7\ g \ Ni}{1\ mol\ Ni}\times\frac{1\ kg\ Ni}{1000\ g\ Ni}= 794\ kg\ Ni $
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