## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 90a

#### Answer

$141\ kg\ Cd$

#### Work Step by Step

1. Use Avogadro's number to convert from atoms to moles of cadmium. Then use the molar mass of cadmium to convert from moles to grams of cadmium. Finally, convert grams into kilograms. 2. $7.55\times10^{26}\ atoms\ Cd\times\frac{1\ mol\ Cd}{6.022\times 10^{23}\ atoms\ Cd}\times\frac{112.4\ g \ Cd}{1\ mol\ Cd}\times\frac{1\ kg\ Cd}{1000\ g\ Cd}= 141\ kg\ Cd$

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