Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 89c

Answer

$ 62\ g\ Pb $

Work Step by Step

1. Use Avogadro's number and the molar mass of lead as conversion factors in order to determine the number of grams of lead. 2. $1.8\times10^{23}\ atoms\ Pb\times\frac{1\ mol\ Pb}{6.022\times 10^{23}\ atoms\ Pb}\times\frac{207.2\ g \ Pb}{1\ mol\ Pb} = 62\ g\ Pb $
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