# Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 89a

$36\ g\ Au$

#### Work Step by Step

1. Use Avogadro's number and the molar mass of gold as conversion factors in order to determine the number of grams of gold. 2. $1.1\times10^{23}\ atoms\ Au\times\frac{1\ mol\ Au}{6.022\times 10^{23}\ atoms\ Au}\times\frac{196.96\ g \ Au}{1\ mol\ Au} = 36\ g\ Au$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.