Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 88a


$1.732\times10^{23}\ atoms\ Cr $

Work Step by Step

1. Use the molar mass of chromium and Avogadro's number as conversion factors in order to determine the number of atoms of chromium. 2. $14.955 g\ Cr \times\frac{1\ mol\ Cr}{51.996\ g\ Cr}\times\frac{6.022\times10^{23}}{1\ mol\ Cr}= 1.732\times10^{23}\ atoms\ Cr $
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