Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 87c

Answer

$5.39\times10^{21}\ atoms\ Bi $

Work Step by Step

1.Use the molar mass of bismuth and Avogadro's number as conversion factors in order to determine the number of atoms of bismuth. 2. $1.87 g\ Bi \times\frac{1\ mol\ P}{208.9804\ g\ Bi}\times\frac{6.022\times10^{23}}{1\ mol\ Bi}= 5.39\times10^{21}\ atoms\ Bi $
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