Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 87b

Answer

$6.78\times10^{21}\ atoms\ Hg$

Work Step by Step

1.Use the molar mass of mercury and Avogadro's number as conversion factors in order to determine the number of atoms of mercury. 2. $2.26 g\ Hg \times\frac{1\ mol\ P}{230.29\ g\ P}\times\frac{6.022\times10^{23}}{1\ mol\ P}= 6.78\times10^{21}\ atoms\ Hg $
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