Chemistry: A Molecular Approach (3rd Edition)

$1.59 g\ Pt$
1. Use Avogadro's number and the molar mass of platinum as conversion factors in order to determine the number of grams of platinum in the sample. 2. $(4.91 \times 10^{23}atoms\ Pt) \times \frac{1 molPt}{6.022 \times 10^{23}}\times \frac{195.081g Pt}{1 mol-Pt} = 1.59 g\ Pt$