Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 86

Answer

$1.59 g\ Pt$

Work Step by Step

1. Use Avogadro's number and the molar mass of platinum as conversion factors in order to determine the number of grams of platinum in the sample. 2. $(4.91 \times 10^{23}atoms\ Pt) \times \frac{1 molPt}{6.022 \times 10^{23}}\times \frac{195.081g Pt}{1 mol-Pt} = 1.59 g\ Pt$
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