Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 82

Answer

$6.1$ $mols$ $Al$

Work Step by Step

1. Use Avogadro's number as a conversion factor in order to find the number of moles of aluminum. 2. $3.7\times10^{24} atoms Al\times\frac{1 mol Al}{6.022\times10^{23} atoms Al}=6.1 mol Al$
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