Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 54b

88 protons, 138 neutrons

Work Step by Step

Atomic number of the isotope $^{226}_{88}Ra$ = 88 = $Z$ Mass number of $^{226}_{88}Ra$ = 226 = $A$ So, number of protons = Atomic number = 88 Number of neutrons = $A - Z = 226-88$ = 138

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