## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 46

#### Answer

Number of electrons needed = $6.25\times10^{18}$ Total mass = $5.6875\times10^{-12}$ kg

#### Work Step by Step

Charge on 1 electron = $-1.6\times10^{-19}$ C Required charge = $-1$ C Number of electrons needed = $\frac{-1}{-1.6\times10^{-19}}$ = $6.25\times10^{18}$ Mass of $1$ electron = $9.1\times10^{-31}$ kg Thus, total mass = $6.25\times10^{18} \times 9.1\times10^{-31}$ = $5.6875\times10^{-12}$ kg

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.