Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Cumulative Problems: 119

Answer

$$106.91 amu$$

Work Step by Step

The mass ratio of Ag-107 and Ag-109 is 1.0187 100% - 51.839% = 48.161% Ag-109 0.51839Z + 0.48161(1.0187Z) = 107.87 amu Solve for Z algebraically: Z= 106.91 amu
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