Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 18 - Sections 18.1-18.9 - Exercises - Problems by Topic - Page 904: 42b

Answer

$4Ag(s) + 8CN^{-}(aq) + O_{2}(g) + 2H_{2}O(l) → 4Ag(CN)_{2}^{-}(aq) + 4OH^{-}(aq)$

Work Step by Step

Since the reaction is in basic medium, we add water to the left hand side and OH- to the right hand side of the equation
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