Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic: 69a

Answer

$463 g$

Work Step by Step

$m= D \times V$ $m= 417mL \times 1.11\frac{g}{mL} = 4.63 \times 10^{2} g = 463g$
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