## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic: 53

#### Answer

$$-80^{o}F=210.93K = -62.22^{o}C$$

#### Work Step by Step

To convert $^{o}F to ^{o}C$, use the following formula: $$^{o}C=(F^{o}-32)\div1.8$$ $$^{o}C=(-80^{o}-32)\div1.8$$ $$^{o}C=-62.22$$ To convert $^{o}C to K$, use the following formula: $$K=^{o}C+273.15$$ $$K=^{o}-62.22+273.15$$ $$K=210.9$$

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