## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 1 - Sections 1.1-1.8 - Exercises - Problems by Topic: 51c

#### Answer

$$-109^{o}F=-78.3^{o}C$$

#### Work Step by Step

Since we are given that $-109^{o}F$ is the temperature of dry ice, we can convert to $^{o}C$: $^{o}C = (-109^{o}F - 32)\div1.8 = -78.3^{o}C$

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