## Chemistry: A Molecular Approach (3rd Edition)

$$77 K = -321^{o}F$$
We know the temperature of liquid nitrogen is $-321^{o}F$ so 77 K must be equal to $-321^{o}F$. To solve mathematically, convert Kelvin to Celsius and then Celsius to Fahrenheit: $^{o}C = K - 273.15$ is our first conversion factor. $^{o}C = 77K - 273.15 = -196.15^{o}C$ $^{o}F = 1.8(^{o}C) + 32$ is our second conversion factor. $^{o}F = 1.8(-196.15^{o}C) + 32 = -321^{o}F$