## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 1 - Sections 1.1-1.8 - Exercises - Cumulative Problems: 108

#### Answer

73$^{\circ}$J

#### Work Step by Step

1. Connect two scales into one expression $\frac{J-17}{80}=\frac{H}{120}$ 2. Simplify the expression multiplying both sides by 40 $\frac{J-17}{2}=\frac{H}{3}$ 3. Given H=84, just substitute and solve for J: $\frac{J-17}{2}=\frac{84}{3}$ $3J-51=168$ $3J=219$ $J = 73$ 4. Therefore, boiling point of methanol in J scale is 73.

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