## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 1 - Sections 1.1-1.8 - Exercises - Cumulative Problems: 106

#### Answer

$-40^{\circ}$

#### Work Step by Step

1. To calculate the common temperature, we use the equation for conversion $C=\frac{F-32}{1.8}$ 2. Since both values are the same, we can indicate them temperature as x, then just solve for x: $C=F=x$ $x=\frac{x-32}{1.8}$ $1.8x=x-32$ $0.8x=-32$ $x=-40$

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