Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 7 - Atomic Structure and Periodicity - Exercises - Page 344: 73

Answer

a.) Correct! b.) Wrong; $m_l$ cannot be 4 if $n=4$. c.) Wrong; $n$ cannot be zero ($n\neq0$). d.) Wrong; $l$ cannot be a negative number.

Work Step by Step

a.) These numbers are CORRECT. Since $n=3$, the value of $l$ can only be between 0 and 2 (0 < $l$ < 2). $m_l$ can only be between -2 and 2 (-2 < $m_l$ < 2). Since both of these are true, part a.) is correct. b.) WRONG since $n=4$, the magnetic quantum number $m_l$ must be a value between -3 and 3. Since $m_l=4$ this is not true and thus part b.) is wrong. c.) WRONG since $n$ cannot equal zero ($n\neq0$). This is because n represents the energy level of an orbital, and the energy level must be greater than 1, thus n > 0. Thus part c.) is wrong. d.) WRONG since $l$ cannot be negative. $l$ represents the sublevel of an orbital corresponding to the s, p, d, and f sublevels. Each sublevel corresponds to a different value of $l$ such that IF $l$ were to equal 0, then the orbital would be in the s sublevel. These sublevels are represented by POSITIVE integers. Therefore, there is no sublevel for $l=-1$. Since the value of $l$ is negative, part d.) is wrong.
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