Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 7 - Atomic Structure and Periodicity - Exercises - Page 343: 55

Answer

$m=1.64\times 10^{-27}Kg$

Work Step by Step

We know that $\lambda=\frac{h}{mv}$ This can be rearranged as: $m=\frac{h}{v\lambda}$ We plug in the known values to obtain: $m=\frac{6.626\times 10^{-34}}{0.90(2.9979\times 10^8)(1.5\times 10^{-15})}$ $m=1.64\times 10^{-27}Kg$
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