Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 7 - Atomic Structure and Periodicity - Exercises - Page 343: 54

Answer

$\lambda=1.32\times 10^{-13}m$ $v=5300\frac{m}{s}$

Work Step by Step

(a) We know that $\lambda=\frac{h}{mv}$ We plug in the known values to obtain: $\lambda=\frac{6.626\times 10^{-34}}{1.67\times 10^{-27}\times (0.01)(2.9979\times 10^8)}$ $\lambda=1.32\times 10^{-13}m$ (b) As $v=\frac{h}{m\lambda}$ We plug in the known values to obtain: $v=\frac{6.626\times 10^{-34}}{1.67\times 10^{-27}\times 75\times 10^{-12}}$ $v=5300\frac{m}{s}$
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