Chapter 7 - Atomic Structure and Periodicity - Exercises - Page 343: 53

$\lambda=2.43\times 10^{-11}m$ $\lambda=3.4\times 10^{-34}m$

(a) As $\lambda=\frac{h}{mv}$ We plug in the known values to obtain: $\lambda=\frac{6.63\times 10^{-34}}{9.11\times 10^{-31}\times 3.00\times 10^7}$ $\lambda=2.43\times 10^{-11}m$ (b) As $\lambda=\frac{h}{mv}$ We plug in the known values to obtain: $\lambda=\frac{6.63\times 10^{-34}}{0.055\times 35}$ $\lambda=3.4\times 10^{-34}m$