Answer
$574.0nm$
Work Step by Step
We know that
$E=\frac{hc}{\lambda}$
This can be rearranged as:
$\lambda=\frac{hc}{E}$
We plug in the known values to obtain:
$\lambda=\frac{6.626\times 10^{-34}\times 2.9979\times 10^8}{3.461\times 10^{-19}}$
$\lambda=5.740\times 10^{-7}m=574.0nm$