Answer
1604.2 grams of $C_{3}$$H_{3}N$
Work Step by Step
PV=nRT
P = .5MPa$\times$1000Kpa = 500Kpa
T = 25 $c^{\circ}$ +273 = 298 Kelvin
V = 150L
R = 8.315 L*Kpa/K*mol
(500Kpa)(150L)=n(8.315)(298)
n = 30.26 mol $C_{3}$$H_{6}$
30.26 mol $C_{3}$$H_{6}$ $\times$ $\frac{2 mol C_{3}H_{3}N }{2 mol C_{3}H_{6}}$ = 30.26 mol $C_{3}H_{3}N$
30.26 mol $C_{3}H_{3}N$ $\times$ $\frac{53grams C_{3}H_{3}N}{1 mol}$ = 1604.2 grams $C_{3}H_{3}N$