Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises - Page 237: 64

Answer

$0.921$

Work Step by Step

We know that $PV=nRT$ $\implies \frac{nT}{V}=\frac{P}{R}=constant$ $\implies \frac{n_1T_1}{V_1}=\frac{n_2T_2}{V_2}$ This can be rearranged as: $\frac{n_2}{n_1}=\frac{T_1V_2}{T_2V_1}$ We plug in the known values to obtain: $\frac{n_2}{n_1}=\frac{294K}{335K}\times \frac{4.20\times 10^3m^3}{4.00\times 10^3m^3}=0.921$
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