Answer
$44.8 \text{ grams $H_2$}$
$88.9 \text{ grams $He$}$
Work Step by Step
$PV=nRT$
$2.70*200.0=n*0.08206*(24+273)$
$n=22.2\text{ mol}$
$22.2\text{1 mol $H_2$}*\frac{\text{2.01588 grams $H_2$}}{1 \text{ mol $H_2$}}=44.8 \text{ grams $H_2$}$
$22.2\text{1 mol $He$}*\frac{\text{4.00260 grams $He$}}{1 \text{ mol $He$}}=88.9 \text{ grams $He$}$
