Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 132: 113

Answer

$7.2*10^4\text{ grams Coke}$

Work Step by Step

$1\text{ ton}*\frac{907185\text{ grams}}{1\text{ ton}}*\frac{1\text{ mol $CuO$}}{79.5454\text{ grams}}*\frac{1\text{ mol C}}{2\text{ mol $CuO$}}*\frac{12.0107\text{ grams C}}{1\text{ mol C}}*\frac{100\text{ grams Coke}}{95\text{ grams C}}=7.2*10^4\text{ grams Coke}$
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