Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Additional Exercises - Page 133: 133

Answer

The empirical formula for Adrenaline is $C_{8}H_{11}O_{3}N$.

Work Step by Step

the first step is to assume we have 100 grams of adrenaline and thus we would have: 56.79 grams of carbon which is nearly 4.7325 moles of carbon.$(56.79 grams / 12 g/mol) = 4.7325$ 6.56 grams of hydrogen which is 6.56 moles of hydrogen. $(6.56 grams / 1.0 g/mol) = 6.56 moles of hydrogen $ 28.37 grams of oxygen which is nearly $(28.37 g / 16 g/mol) = 1.77 moles of oxygen $ and finally, 8.28 grams of nitrogen which is $(8.28 g / 14 g/mol) = 0.59 moles of nitrogen $ since the empirical formula is by definition the simplest ratio of moles of different atoms in a compound. We would divide by the smallest number of moles (here is nitrogen = 0.59 ) to get whole numbers or integers. dividing each of the above by 0.59 would give: 8 moles of carbon 11 moles of hydrogen 3 moles of oxygen and any number by himself is just 1, just like nitrogen moles here. reconstructing the formula would give the empirical formula for Adrenaline is $C_{8}H_{11}O_{3}N$.
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