Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 2 - Atoms, Molecules, and Ions - Additional Exercises: 101

Answer

a) Element - Phosphorus (P) Number of protons = 15 Number of neutrons = 16 b) Element - Iodine (I) Number of protons = 53 Number of neutrons = 74 c) Element - Potassium (K) Number of protons = 19 Number of neutrons = 20 d) Element - Ytterbium (Yb) Number of protons = 70 Number of neutrons = 103

Work Step by Step

a) Mass number = A = 31 Atomic number = Z = 15 So the atom with atomic number 15 is Phosphorus (P) Thus, number of protons = Atomic number = Z = 15 Also, number of neutrons = A - Z = 31 - 15 = 16. b) Mass number = A = 127 Atomic number = Z = 53 So the atom with atomic number 53 is Iodine (I) Thus, number of protons = Atomic number = Z = 53 Also, number of neutrons = A - Z = 127 - 53 = 74. c) Mass number = A = 39 Atomic number = Z = 19 So the atom with atomic number 19 is Potassium (K) Thus, number of protons = Atomic number = Z = 19 Also, number of neutrons = A - Z = 39 - 19 = 20. d) Mass number = A = 173 Atomic number = Z = 70 So the atom with atomic number 70 is Ytterbium (Yb) Thus, number of protons = Atomic number = Z = 70 Also, number of neutrons = A - Z = 173 - 70 = 103.
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