Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 12 - Chemical Kinetics - Questions: 22

Answer

The slope of a $ln(k)$ versus $\frac{1}{T}$ plot for a catalyzed reaction would be less negative.

Work Step by Step

The slope of a $ln(k)$ vs $\frac{1}{T}$ plot is equal to $\frac{-E_a}{R}$. A catalyzed reaction has a lower $E_a$ than an uncatalyzed one, and $R$ remains constant, so the slope should be less negative.
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