Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 1 - Chemical Foundations - Integrative Problems: 120

Answer

Density = $22.61$ $\frac{g}{cm^{3}}$ Mass = $16279.2$ grams

Work Step by Step

Density in $\frac{kg}{m^{3}}$ = 22610. 1 $\frac{kg}{m^{3}}$ = $\frac{1000g}{(100cm)^{3}}$ = $\frac{1000g}{100000 cm^{3}}$ = $\frac{1g}{1000cm^{3}}$ Thus, 1000$\frac{kg}{m^{3}}$ = $\frac{1g}{cm^{3}}$ So, 22610 $\frac{kg}{m^{3}}$ = $\frac{22610g}{1000 cm^{3}}$ = 22.61 $\frac{g}{cm^{3}}$ Now, dimensions are 10 cm $\times$ 8 cm $\times$ 9 cm Hence volume = (10 $\times$ 8 $\times$ 9) $cm^{3}$ = 720 $cm^{3}$ Since Density = $\frac{Mass}{Volume}$ Hence Mass = Density $\times$ Volume = 22.61 $\times$ 720 = $16279.2$ grams
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.