Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 1 - Chemical Foundations - Exercises: 70

Answer

Answer: Mass of mixture = 958.9 grams

Work Step by Step

To calculate total mass of mixture, we need to calculate the masses of ethanol and benzene separately. Ethanol: 1 ml = 1 $cm^{3}$ ........(i) Thus, 100 mL = 100 $cm^{3}$ From table 1.5, density of ethanol is = 0.789 $\frac{g}{cm^{3}}$ Thus mass = density $\times$ volume = 100 $\times$ 0.789 = 78.9 grams Mass of Benzene: Volume = 1 liter = 1000 ml = 1000 $cm^{3}$ ....(From (i)) Given density = 0.88 $\frac{g}{cm^{3}}$ Thus mass = 0.88 $\times$ 1000 = 880 grams Final or total mass of mixture = 880 + 78.9 = 958.9 grams
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