Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 1 - Chemical Foundations - Exercises: 68

Answer

Volume = 101.5 $cm^{3}$ Density = 6.059 $\frac{g}{cm^{3}}$ = 6059$\frac{kg}{m^{3}}$

Work Step by Step

Given: Dimensions - 2.9 cm $\times$ 3.5 cm $\times$ 10 cm Mass = 615.0 g Volume of rectangular block = Length $\times$ breadth $\times$ height = 2.9 cm $\times$ 3.5 cm $\times$ 10 cm $\therefore$ Volume = 101.5 $cm^{3}$ Since Density = $\frac{Mass}{Volume}$ = $\frac{615}{101.5}$ $\therefore$ Density = 6.059 $\frac{g}{cm^{3}}$ Since 1$\frac{g}{cm^{3}}$ = 1000$\frac{kg}{m^{3}}$ 6.059 $\frac{g}{cm^{3}}$ = 6059$\frac{kg}{m^{3}}$
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