Answer
Please see the work below.
Work Step by Step
We know that the number of lone pairs on the underlined atoms in the given compounds are as follows
$HBr$ has 1 lone pairs.
$H_2S$ has 2 lone pairs.
$CH_4$ has 0 lone pairs.
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 9 - Chemical Bonding I - Questions & Problems - Page 404: 9.30
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