Answer
Please see the work below.
Work Step by Step
We know that
$\lambda=\frac{hc}{E}$
We plug in the known values to obtain:
$\lambda=\frac{6.63\times 10^{-34}(3.00\times 10^{17})}{5.60\times 10^{-19}}=355nm$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 8 - Periodic Relationships Among the Elements - Questions & Problems - Page 365: 8.109
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