Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 8 - Periodic Relationships Among the Elements - Questions & Problems: 8.109

Answer

Please see the work below.

Work Step by Step

We know that $\lambda=\frac{hc}{E}$ We plug in the known values to obtain: $\lambda=\frac{6.63\times 10^{-34}(3.00\times 10^{17})}{5.60\times 10^{-19}}=355nm$
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