Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 6 - Thermochemistry - Questions & Problems - Page 263: 6.28

Answer

$w=0$ $\Delta U=-553.8\,kJ/mol$

Work Step by Step

$\Delta n=\text{number of moles of product gas}-\text{number of moles of reactant gases}$ $=6-(3+3)=0$ $w=-\Delta(nRT)=RT(0)=0$ $\Delta U= \Delta H-\Delta(nRT)$ $=\Delta H-RT\Delta n=\Delta H-RT(0)=\Delta H$ As we multiplied the given equation by 3, $\Delta U=\Delta H=3\times-184.6\,kJ/mol=-553.8\,kJ/mol$
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