Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 6 - Thermochemistry - Questions & Problems - Page 263: 6.27

Answer

480 kJ/mol

Work Step by Step

$\Delta n=\text{number of moles of product gases}-\text{number of moles of reactant gas}$ $=3-2=1$ $\Delta U= \Delta H-\Delta(nRT)$ $=\Delta H-RT\Delta n$ $=483.6\times10^{3}\,J/mol-(8.314\,J\,mol^{-1}K^{-1})(273+125)K\times(1)=4.80\times10^{5}\,J/mol$ $=480\,kJ/mol$
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