Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 217: 5.54

Answer

$ 370 L$

Work Step by Step

Given information Combustion process $CH_{4} + 2O_{2}-->CO_{2}+2H_{2}O$ 15 moles$ CH_{4}$ are reacted T=23°C=296K P=0.985 atm $R=0.0821atmL/molK$ By this reaction, we can say that 15 moles methane gives 15 moles carbon dioxide. PV=nRT V(volume of $CO_{2}$)=$\frac{nRT}{P}$ V=$\frac{15*0.0821*296}{0.985}$ V=370L
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