Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems: 5.34

Answer

Please see the work below.

Work Step by Step

We know that: $T_2=\frac{P_2T_1}{P_1}$ We plug in the known values to obtain: $T_2=\frac{2\times 298}{0.8}=745K$ $T_2=745K=472C^{\circ}$
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