Answer
Please see the work below.
Work Step by Step
We know in the given scenario $Moles \space of \space NaOH:HCl=1:1$
We plug in the known values to obtain:
$0.0174L\space HCl\times 0.312\frac{mol}{HCl}=0.0054mol\space NaOH$
$Molarity\space of\space NaOH=\frac{0.0054mol}{0.0025L}=0.217\frac{mol}{L}$
