Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 4 - Reactions in Aqueous Solutions - Questions & Problems: 4.90

Answer

Please see the work below.

Work Step by Step

We know in the given scenario $Moles \space of \space NaOH:HCl=1:1$ We plug in the known values to obtain: $0.0174L\space HCl\times 0.312\frac{mol}{HCl}=0.0054mol\space NaOH$ $Molarity\space of\space NaOH=\frac{0.0054mol}{0.0025L}=0.217\frac{mol}{L}$
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