Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 3 - Mass Relationships in Chemical Reactions - Questions & Problems - Page 108: 3.51

Answer

Ca = 34.5% $\qquad$ Si = 24.2%$\qquad$O = 41.3%

Work Step by Step

$\qquad$To find the percent composition of CaSiO₃, First we have to find its molecular weight. Molar masses of Calcium, Silicon and Oxygen are: $\qquad$$Ca = 40.1 g/mol $ $\qquad$ $ Si = 28.1 g/mol $ $\qquad$ $ O = 16.0 g/mol$ So, $\qquad$The molecular weight of $ CaSiO₃ =[ 40.1 g/mol+ 28.1 g/mol + (3)16.0 g/mol ]= 116.2 g/mol$ Now the percent composition of each element is : % Ca= [40.1g/mol $\times$$\left ( \frac{1 molCa }{116.2g} \right )$] $\times$ 100 = 34.5% Ca % Si =[ 28.1g/mol $\times$$\left ( \frac{1 molSi }{116.2g} \right )$ ] $\times$ 100 = 24.2% Si % O = [16.0g/mol $\times$$\left ( \frac{1 molO }{116.2g} \right )$ ] $\times$ 100= 41.3% O So The percent composition of CaSiO₃ is found to be 34.5% Calcium 24.2% Silicon and 41.3% Oxygen.
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